Vector Is Not A Template

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This however is rather unwielding. Just get iter underlying type either using decltype or using iterator. You have to do this because vector is defined in the std. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> Vector in the function signature.

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Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. Anyway define a type instead of a macro. You have to do this because vector is defined in the std. Everywhere qualify it by std:: Commented jun 24, 2020 at 9:39.

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Since you're passing a pointer to a vector you need to. It is not true that the type is not known. You have to do this because vector is defined in the std. Commented jun 24, 2020 at 9:39. Vector in the function signature.

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Vector is a template, not a type, you need the template argument list e.g. This however is rather unwielding. Vector in the function signature. You have to do this because vector is defined in the std. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p>

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The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. This however is rather unwielding. Just get iter underlying type either using decltype.

Vector Is Not A Template - Anyway define a type instead of a macro. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. You're getting the errors because u64 is not defined at that point. Anyway define a type instead of a macro. If we start in node.h, early on, it includes edge.h. As some commenters have noted, you have circular references.

Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be. Therefore the compiler needs to know the declaration of std::vector at that point (amongst other things,.</p> Everywhere qualify it by std:: This however is rather unwielding. You're getting the errors because u64 is not defined at that point.

As Some Commenters Have Noted, You Have Circular References.

Everywhere qualify it by std:: It is not true that the type is not known. Vector is a template, not a type, you need the template argument list e.g. Since you're passing a pointer to a vector you need to.

The Type Of The Vector You Want To Create Is Of The Same Kind Of Iter.

Anyway define a type instead of a macro. You have to do this because vector is defined in the std. The code is parsed in the order it appears. Vector in the function signature.

This However Is Rather Unwielding.

Just get iter underlying type either using decltype or using iterator. Commented jun 24, 2020 at 9:39. You're getting the errors because u64 is not defined at that point. The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion.

Therefore The Compiler Needs To Know The Declaration Of Std::vector At That Point (Amongst Other Things,.</P>

If we start in node.h, early on, it includes edge.h. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector. Anyway define a type instead of a macro. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be.